a = b ab = b2 ab − a2 = b2 − a2 a(b−a) = (b+a) (b−a) a = b + a a + 1 = b + a + 1 Since a = b , a + 1 = 2a + 1 1 + 1 = 2 + 1 Therefore, 1 + 1 = 3
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